ESR法研究Pt催化N2H4分解机制

Mechanism of Pt-catalyzed N2H4 Decomposition by ESR Method

  • 摘要: 采用电子自旋共振谱(ESR)法,研究了酸性条件下•NH2的转化,HClO4体系下反应时间对溶液中自由基产生的影响、pH值对N2H4断键的影响以及HNO3中N是否对溶液中的•NH2有贡献,确定了Pt催化N2H4分解的反应机理。结果表明:在酸性条件下•NH2被DMPO捕捉时反应式为•NH+3+HO—H+DMPO=NH+4+DMPO(•OH),硝酸在Pt催化N2H4体系中不会发生断键产生•NH2,所产生的•NH2是由N2H4断键形成的;在HClO4体系中,随着Pt催化N2H4反应时间的延长,N2H4中N—N断键的趋势逐渐减小,N—H断键的趋势逐渐增大;随pH值的增大,N2H4中N—N断键的速率先快速减小,pH>3后缓慢增大;Pt催化N2H4分解反应中N—N断键和N—H断键两种方式共存,但N—N断键占优;反应体系中N2H4与H浓度之比决定了N—N断键生成•NH2的速率,而•NH2与H的浓度又决定了•NH2转化成产物的速率,这两方面共同决定了N2H4分解的速率。

     

    Abstract: Electron spin resonance (ESR) method was used in researching the conversion of •NH2 under acidic conditions, the effect of reaction time on the free radical production in HClO4 system, the effect of pH on the broken bond of N2H4, and whether N in HNO3 impacts on the production of •NH2. The reaction mechanism of N2H4 catalyzed by Pt was determined. The results show that the reaction of •NH2 captured by DMPO under acidic conditions is •NH+3+HO—H+DMPO=NH+4+DMPO(•OH). In Pt-catalyzed N2H4 the HNO3 doesn’t break bond, and the •NH2 is only from N2H4. In the HClO4 system, as the reaction proceeds, the trend of N—N bond-breaking in N2H4 decreases gradually and the trend of N—H bond-breaking increases gradually. With the increase of pH, the rate of N—N bond-breaking in N2H4 decreases rapidly and then increases slowly after pH>3, N—N bond-breaking and N—H bond-breaking coexist in Pt-catalyzed N2H4 decomposition process, but the N—N bond-breaking is dominant. In the reaction system, the concentration ratio of H+ to N2H+4 determines the formation rate of •NH2 from N—N bond breaking, the concentrations of •NH2 and H also determine the rate of •NH2 converted to the products, and the two aspects determine the rate of N2H4 decomposition together.

     

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